The original number


I bought a car with a peculiar 5 digit numbered licence plate which on reversing could still be read. On reversing, its value is increased by 78633. Whats the original number if all digits are different?

For Solution SCROLL DOWN....


Only 0 1 6 8 and 9 can be read upside down. So on rearranging these digits we get the answer as 10968.


Dharmendra said...



pg... said...

answer is 10968.

i)we can't read 2,3,4,5,7 while they are reversed.
ii)so that number is built with 1,6,8,9,0.
iii) difference between both numbers is 78633.
iv)both the numbers are 5 digits. units place difference is 3, so 0(zero is not at the both the ends)

v) 10 thosands place difference is 7. units place difference is 3
this is possible only through 8,1 numbers( because 8-1= 7 and 11 -8 =3)(another pair to getting difference 3 is (9-6) but 6-9 not equal to 7 so this is not the pair),
So in actual number plate ones place is 8 and tenthosands place is 1.

vi) in thousands place we have to get the difference is 8 and tenths place difference have to get 3 ( the only one possible way is ((9-1) -0)and (10-1-6) because( 1, 8 allready placed at the end positions) .
Considering all above cases
actual number is 10968

enigma said...

answer is 10968

Jayant said...

yup, 10968...
But the question is worded incorrectly...It should read as "upturned" or "inverted" and not "reversed"...Though ofcourse, we usually dont have a transparent license plate, so if we reverse it as such, we wont see a thing :D (unless a mirror reflection)...

poojarini said...


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