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$10K Will

Puzzle:

A man leaves $10,000 in his will, to which there are 6 beneficiaries - his three sons and their wives. The 3 wives receive $3,960 of which Jennifer gets $100 more than Rachel and Holly gets $100 more than Jennifer. Of the sons, James gets twice as much as his wife, Eric gets the same as his wife, and Sam gets 50% more than his wife. Who is married to whom?

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Solution:

Jennifer is married to Sam.
Rachel is married to Eric.
James is married to Holly.

Three Kids

Puzzle:

There are three kids and each one have some pencils. The first kid gave the second and third as many pencils as they each already had. Then, the second gave the first and third as many as they each had. Still later, the third gave the first and second as many as they each already had. Each kid now have 24 pencils. How many pencils did each kid have originally?

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Solution:

You can solve the problem easily backward

First+Second+Third

24 + 24 + 24 = 72

12 + 12 + 48 = 72

6 + 42 + 24 = 72

39 + 21 + 12 = 72

The first had 39 pencils, the second had 21 and the third had 12.

Clock in the Mirror

Puzzle:

Today, in the morning, while going to college, I looked at the clock in the mirror. The clock has no number indication and I made a mistake in interpreting the time (mirror-image). Assuming that the clock must be out of order, I went to college, where I arrive after twenty minutes. At that moment the clock at college shows a time that is two and a half hours later than the time that I saw on the clock (mirror-image) at home. At what time did I reach college?

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Solution:

I reached college at twenty-five minutes past seven.

The difference between the real time and the time of the mirror image is two hours and ten minutes (two and a half hours, minus the twenty minutes to reach college). Therefore, the original time on the clock at home that morning could only have been five minutes past seven (4:55 in the mirror). I reaches college at five minutes past seven plus twenty minutes, which is twenty-five minutes past seven!...

Guessing Contest

Puzzle:

In a contest, five fruits (an apple, a banana, an orange, a strawberry and a pear) have been placed in five closed boxes (one fruit per box). People may guess which fruit is in which box. 107 people participate in the contest. When the boxes are opened, it turns out that 40 people have guessed none of the fruits correctly, 30 people have guessed one fruit correctly, 20 people have guessed two fruits correctly and 10 people have guessed three fruit correctly. How many people have guessed four fruits correctly and how many people have guessed all the fruits correctly?

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Solution:

It is not possible to guess only four fruits correctly: the fifth fruit is then correct too! So nobody has guessed four fruits correctly and 107-40-30-20-10 = 7 people have guessed five fruits correctly.


Hourglasses

Puzzle:

There are two hourglasses. The small one can measure 5 minutes and the large one can measure 7 minutes. How can we measure 16 minutes with 2 hourglasses running together? (If one of the hourglasses finishes leaking, then it must be flipped over immediately to keep it running. )


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Solution:

Start both hourglasses at the same time. You flip over the small hourglass when it finishes the first 5 minutes. Then you flip over the large one when it finishes its first 7 minutes. When the small hourglass runs to 10 minutes, flip over the small and large hourglass at the same time. It means the large hourglass will run 3 minutes again. When the large hourglass run to 13 minutes (7 + 3 + 3), flip both the small and large hourglass over again to run another 3 minutes.



Digits 1 to 6

Puzzle:

Take a look at the following multiplication problem. Replace all "?" with digits 1, 2, 3, 4, 5 and 6 (use one digit only once) to make it true.

? ?
x ?
___
? ? ?

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Solution:

54
x 3
-----
162
-----



Spider, Dragonfly & Cicada

Puzzle:

A spider has 8 legs. A dragonfly has 6 legs and 2 pairs of wings. A cicada has 6 legs and one pair of wings. Now we have all 3 kinds and a total of 18 insects in a cage. We have a total of 118 legs and 20 pairs of wings. How many insects do we have of each kind?

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Solution:

There are Five Spiders, Seven Dragonflies & Six Cicada.

Let X be the number of spiders, Y be number of Dragonflies and Z be number of cicada. Now from the puzzle,
X+Y+Z = 18
8X+6Y+6Z = 118
2Y+Z = 20
Solving this, X=5, Y=7, Z=6




A Barrel

Puzzle:

There is a barrel with no lid and some wine in it.
"This barrel of wine is more than half full," said Kiran.
"No it's not," says Rahul. "It's less than half full."

Without any measuring implements and without removing any wine from the barrel, how can they easily determine who is correct?

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Solution:

Tilt the barrel until the wine barely touches the lip of the barrel. If the bottom of the barrel is visible then it is less than half full.If the barrel bottom is still completly coverd by the wine, then it is more than half full.


Marbles

Puzzle:

In a box you have 13 white marbles and 15 black marbles. You also have 28 black marbles outside the box. Remove two marbles, randomly, from the box. If they are of different colors, put the white one back in the box. If they are the same color, take them out and put a black marble back in the box. Continue this until only one marble remains in the box. What color is the last marble?

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Solution:

The last marble will be WHITE.

Since marbles can only be taken out in pairs and you started off with an odd number of whites there is always going to be one white left over that you'll keep putting back in the box until it's left on it's own.



5 Digit Number

Puzzle:

There is a 5 digit number. With a 1 after it, it is three times as large as it would be with a one before it. What is the 5 digit number?

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Solution:

The 5 digit number is: 42857

The number with a one after it is 10x + 1. With a 1 before it, it is 100,000 + x. Then 10x +1 = 3(100,000 + x), and x = 42,857. Therefor the 5 digit number is: 42857

Guests

Puzzle:

A cook wanted to find out how many guests she cooked for. An official told her that for every dish of rice, there were 2 people. And every three people had a dish of broth. There was 1 dish of meat for every four people. There were 65 dishes in all. The cook then figured out how many guests there were. How many guests did the cook cook for?


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Solution:

60 guests

Let x be the number of guests. According to the puzzle, the equation for total number of dishes is x/2 + x/3 + x/4 = 65. Solving this, we get x=60.

Dog, Cow and Goat

Puzzle:

A Dog, a Cow and a Goat were stolen. Three suspects got caught: Raghu, Kiran and Sam. Each person stole one animal, but we do not know who stole which. Here are the investigation statements.
  • Raghu said: Sam stole the Dog.
  • Kiran said: Sam stole the Cow.
  • Sam said: They both were lying. I did not steal the Dog or the Cow.
Later on, the police found out the man who stole the goat told a lie. The man who stole the dog told the truth. Can you find out who stole which?


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Solution:

Sam stole the Cow
Raghu stole the Goat
Kiran stole the Dog

The man who stole the dog told the truth. All we need to do is to find out who was that.
If Raghu had stolen the dog he would not said: Sam stole the dog. He should said: I stole the dog or Sam did not steal the dog. If Sam had stolen the dog, he would not said: I did steal the dog.
So Kiran stole the dog. What he said was true: Sam stole the cow. Then Raghu stole the goat and told a lie.

A to I are 1 to 9

Puzzle:

Look at the calculation below. Every alphabet represents a different digit from 1 to 9 to make the calculation. What are they?



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Solution:

A=1, B=7, C=4, D=6, E=8, F=2, G=5, H=9, I=3




Two Numbers

Puzzle:

There are two numbers. One larger and the other is smaller. If we subtract half of the smaller number from both numbers then the resultant larger number is 3 times larger as large as the resultant with the orignianl smaller and its half. How many times is the original larger number bigger than the original smaller number?



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Solution:

The original larger number is two times bigger than the original smaller number.

Make a Square

Puzzle:

Put together all the five pieces shown below to form a square. (Print the picture to solve it easily).



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Solution:




Walking Home

Puzzle:

Every day, a wife picks up her husband at train station at 5. One day he arrives early at 4 and he begins to walk home along the road which his wife would be traveling. She meets him and takes him the rest of the way. If he would have waited at the train station, she would have arrived there at 5. As it turned out, they reached home 20 minutes early. What time was it when she picked him up?


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Solution:

It was 4:50

If they made it home 20 minutes early, then the trip was 20 minutes shorter. Then it was 10 minutes shorter going, and 10 minutes shorter coming back home. Since it was 10 minutes shorter going, then she picked him up at 10 'til 5:00, or 4:50.


Handshaking

Puzzle:

Jack and his wife went to a party where four other married couples were present. Every person shook hands with everyone he or she was not acquainted with. When the handshaking was over, Jack asked everyone, including his own wife, how many hands they shook. To his surprise, Jack got nine different answers. How many hands did Jack's wife shake ?


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Solution:

Jack's wife shook 4 hands.

Because, obviously, no person shook hands with his or her partner, nobody shook hands with more than eight other people. And since nine people shook hands with different numbers of people, these numbers must be 0, 1, 2, 3, 4, 5, 6, 7, and 8. The person who shook 8 hands only did not shake hands with his or her partner, and must therefore be married to the person who shook 0 hands. The person who shook 7 hands, shook hands with all people who also shook hands with the person who shook 8 hands (so in total at least 2 handshakes per person), except for his or her partner. So this person must be married to the person who shook 1 hand. The person who shook 6 hands, shook hands with all people who also shook hands with the persons who shook 8 and 7 hands (so in total at least 3 handshakes per person), except for his or her partner. So this person must be married to the person who shook 2 hands. The person who shook 5 hands, shook hands with all people who also shook hands with the persons who shook 8, 7, and 6 hands (so in total at least 4 handshakes per person), except for his or her partner. So this person must be married to the person who shook 3 hands. The only person left, is the one who shook 4 hands, and which must be Jack's wife. The answer is: Jack's wife shook 4 hands.

The Circus

Puzzle:

A circus performance is witnessed by 120 people who have paid a total of $120. The men pay $5, women pay $2, and children pay 10 cents each. How many of each went to the circus?


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Solution:

17 men, 13 women, 90 children went to the circus.


Snail in the well

Puzzle:

A snail is at the bottom of a well 30 feet deep. It crawls up 3 feet each day, but at night, it slips down 2 feet. How long does it take for the snail to crawl out the well?


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Solution:

28 days. Once it reaches the top, it does not slip down 2 feet.

On a Train

Puzzles:

On a train, Smith, Robinson, and Jones are the fireman, brakeman, and the engineer, but not respectively. Also aboard the train are three businessmen who have the same names: a Mr. Smith, a Mr. Robinson, and a Mr. Jones.
  • Mr. Robinson Lives in Detroit.
  • The brakeman lives exactly halfway between Chicago and Detroit
  • Mr. Jones earns exactly $20,000 per year.
  • The brakeman's nearest neighbor, one of the passengers, earns exactly three times as much as the brakeman.
  • Smith beats the fireman in billiards.
  • The passenger whose name is the same as the brakeman's lives in Chicago.
Who is the Engineer?


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Solution:

Smith is the engineer.

Love Story

Puzzle:

Four men and four women are shipwrecked on a desert island. Eventually each one falls in love with one another, and is himself loved by one person. John falls in love with a girl who is in love with Jim. Arthur loves a girl who loves the man who loves Ellen. Mary is loved by the man who is loved by the girl who is loved by Bruce. Gloria hates Bruce and is hated by the man whom Hazel loves. Who loves Arthur?


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Solution:

Gloria loves Arthur.

Find Next Number

Puzzle:

Do you know numbers and letters? Now find the next number in the series.

5.. 15 ..5.. 18.. 5.. 24 ..14.. 20.. ?


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Solution:

Next number is 5.

Write the numbers in words. onE, twO, threE, fouR......
Look at the last letter in each word and convert it into position of letter in the alphabet (E=5, O=15, E=5, R=18.....). Following the pattern, the next word is ninE and position of E is 5 in alphabet.

Count Triangles

Puzzle:

Take a look at the figure below. Can you count number of different triangles in this hexagonal pattern?




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Solution:

There are 76 triangles.



Box and Locks

Puzzle:

You want to send a valuable object to a friend. You have a box to contain the object. The box has a locking ring which is more than large enough to have a lock attached. You and your friend have several locks with keys. But your friend does not have the key to any lock that you have, and vice versa. How do you do it? Note that you cannot send a key in an unlocked box, since it might be copied.


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Solution:

Attach a lock to the ring. Send it to her. She attaches her own lock and sends it back. You remove your lock and send it back to her. She removes her lock.


A Number

Puzzle:

A number when divided by 3 gives a remainder of 1; when divided by 4, gives a remainder of 2; when divided by 5, gives a remainder of 3; and when divided by 6, gives a remainder of 4. Find the smallest such number.


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Solution:

The number is 58.

LCM of 3, 4, 5 and 6 is 60. So these numbers when divides 60 gives remainder 0. Now to get the remainder 1, 2, 3 and 4 respectively, the number should be 2 (3-1 ; 4-2 ; 5-3 ; 6-4 ) short of 60.

Odd One Out

Puzzle:

Which of the following formula is different from others?

  • 100/11
  • 100/22
  • 100/33
  • 100/44
  • 100/55
  • 100/66
  • 100/77
  • 100/88
  • 100/99
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Solution:

The answer is 100/77

  • 100 / 11 = 9.09090909090909090909090909090909
  • 100 / 22 = 4.54545454545454545454545454545455
  • 100 / 33 = 3.03030303030303030303030303030303
  • 100 / 44 = 2.27272727272727272727272727272727
  • 100 / 55 = 1.818181818181818181818181818181818
  • 100 / 66 = 1.51515151515151515151515151515152
  • 100 / 77 = 1.2987012987012987012987012987013
  • 100 / 88 = 1.13636363636363636363636363636364
  • 100 / 99 = 1.01010101010101010101010101010101
The result of 100/77 is odd to all other result.

Paddy Field

Puzzle:

A farmer was getting old and so he decided to divide his paddy field between himself and his four sons in proportion to their work rates. He knew that Rahul, Anil, Sunil and Vineel together could plant a field in five hours whereas Anil, Sunil and Vineel and himself together could manage the same task in six hours. So the farmer divided his field into a two-digit square number of parts and kept just one part for himself. Now, Anil, Sunil and Vineel were identical triplets so each received the same whole number of parts. How many parts did each son get?


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Solution:

Ravi received 9 parts and the triplets each got 13 parts. Let the work rates of the triplets combined, Ravi and farmer be x, y, z, respectively. Then

5(x + y) = 6(x + z) and so y = (x + 6z)/5

Since z has one part, we can let x = nz where n is a whole number. We then have y = (6 + n)z/5. The ratio of the work rates of x, y, z is now

n : (6 + n)/5 : 1

Let the total of parts be m, a two-digit square number. We then have n + (6 + n)/5 + 1 =m so that n = (5m - 11)/6. The only solutions are n=19, m=25 or n=39, m=49. Since n is the total number of parts the triplets receive, only the value divisible by three applies (n=39).




Make "+" Sign

Puzzle:

Look at the six pieces below. Combine these pieces such that they form a symmetrical plus sign.




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Solution:



Departmental Store

Puzzle:

I went to the departmental store and spent one half of the money that was in my purse. When I came out, I found that I had as many paise as I had rupees and half as many rupees as I had paise when I went in. Find the money in my purse when I entered the store.

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Solution:

I have Rs. 99.98 in my purse when I entered the store.


Ten True Sentences

Puzzle:

Take a look at the following sentences:

  • The number of times the digit 0 appears in this puzzle is _____.
  • The number of times the digit 1 appears in this puzzle is _____.
  • The number of times the digit 2 appears in this puzzle is _____.
  • The number of times the digit 3 appears in this puzzle is _____.
  • The number of times the digit 4 appears in this puzzle is _____.
  • The number of times the digit 5 appears in this puzzle is _____.
  • The number of times the digit 6 appears in this puzzle is _____.
  • The number of times the digit 7 appears in this puzzle is _____.
  • The number of times the digit 8 appears in this puzzle is _____.
  • The number of times the digit 9 appears in this puzzle is _____.
Fill these sentences with digits such that all the sentences holds true.


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Solution:

The number of times the digit 0 appears in this puzzle is 1.
The number of times the digit 1 appears in this puzzle is 7.
The number of times the digit 2 appears in this puzzle is 3.
The number of times the digit 3 appears in this puzzle is 2.
The number of times the digit 4 appears in this puzzle is 1.
The number of times the digit 5 appears in this puzzle is 1.
The number of times the digit 6 appears in this puzzle is 1.
The number of times the digit 7 appears in this puzzle is 2.
The number of times the digit 8 appears in this puzzle is 1.
The number of times the digit 9 appears in this puzzle is 1.

Alternative Solution:
The number of times the digit 0 appears in this puzzle is 1.
The number of times the digit 1 appears in this puzzle is 11.
The number of times the digit 2 appears in this puzzle is 2.
The number of times the digit 3 appears in this puzzle is 1.
The number of times the digit 4 appears in this puzzle is 1.
The number of times the digit 5 appears in this puzzle is 1.
The number of times the digit 6 appears in this puzzle is 1.
The number of times the digit 7 appears in this puzzle is 1.
The number of times the digit 8 appears in this puzzle is 1.
The number of times the digit 9 appears in this puzzle is 1.